Answered: Two Snowcats In Antarctica Are Towing A… | Bartleby

Two snowcats tow a housing unit to a new location at McMurdo Base, Antarctica, as shown in Figure 4-46. The sum of the forces A and B exerted on the unit by the horizontal cables is parallel to the line L, and FA = 4200 N. Determine FB and the magnitude of A + B. FB _____ N. FA + FB ____ N. I dont know how to do that.two snowcats tow. Two snowcats tow a housing unit to a new location at McMurdo Base, Antarctica, as shown in the figure . The sum of the forces Fa and Fb exerted on theunit by the horizontal cables is parallel to the line L , and Fa= 4800N.Part ADetermine .Part BDetermine the magnitude of .Two snowcats in Antarctica are towing a housing unit to a new location, as shown in the figure (Figure 1). The sum of the forces F⃗ A and F⃗ B exerted on the unit by the horizontal cables is parallel to the line L, and FA=4400 N. Determine F B. Determine the magnitude of FPhysics 101 Mechanics Sept. 29, 2020, 6:51 p.m. Two snowcats in Antarctica are towing a housing unit north, as shown in the figure below. The sum of the forces \vec {F}_A and \vec {F}_B exerted on the unit by the horizontal cables is north, parallel to the line L, and FA = 4703.3 N. Determine FB.Two snowcats tow a housing unit to a new location at McMurdo Base, Antarctica. FA =611.1 N. The sum of the forces FA (at 50 degrees from L) and FB (at 30 degrees from L) exerted on the unit by the horizontal cables is parallel to the line L. (L= a 90 degree vertical line between the two forces) Determine the magnitude of FA + FB .

26. (II) Two snowcats in Antarctica are towing a housing

Two snowcats tow a housing unit to a new location at McMurdo Base, Antarctica, as shown in Figure 4-46. The sum of the forces A and B exerted on the unit by the horizontal cables is parallel to the line L, and FA = 3500 N. Determine FB and the magnitude of A + B. The figure shows a house being towed by two snowcats.Two snowcats in Antarctica are towing a housing unit to a new location, as shown in the figure. The sum of the forces FA and FB exerted on the unit by the horizontal cables is parallel to the line L, and F A =4600 N. (a) Determine F B. (b) Determine the magnitude of FA + FB.Two snowcats in Antarctica are towing a housing unit to a new location, as shown in Fig. 4-38. The sum of the forces Fa and Fg exerted on. Two snowcats in Antarctica are towing a housing unit to a new location, as. shown in Fig. 4-38.Two snowcats tow a housing unit to a new location at McMurdo Base, Antarctica, as shown in Figure 4-46. The sum of the forces A and B exerted on the unit by the horizontal cables is parallel to the...

26. (II) Two snowcats in Antarctica are towing a housing

Solved: Two Snowcats In Antarctica Are Towing A Housing Un

Two snowcats tow a housing unit to a new location at McMurdo Base, Antarctica, as shown in the figure(Figure 1). The sum of the forces F?Two snowcats in Antarctica are towing a housing unit north, as shown in Fig. 4-50. The sum of the forces F → A and F → B exerted on the unit by the horizontal cables is north, parallel to the line L, and F A = 4500 N. Determine F B and the magnitude of F → A + F → B. Figure 4-50.Two snowcats tow a housing unit to a new location at McMurdo Base, Antarctica, as shown in Figure 4-46. The sum of the forces A and B exerted on the unit by the horizontal cables is parallel to the line L, and FA = 4300 N. Physics . A tow truck pulls a car from rest onto a level road.Two snowcats in Antarctica are towing a housing unit to a new location, as shown. The sum of the forces →F A F → A and →F B F → B exerted on the unit by the horizontal cables is parallel to the...(II) Two snowcats in Antarctica are towing a housing unit north, as shown in Fig. 4-50. The sum of the forces F → A and F → B exerted on the unit by the horizontal cables is north, parallel to the line L, and F A = 4500 N Determine F B and the magnitude of F → A + F → B.

We're requested to resolve FB and the magnitude of the sum of the two forces. 

This problem comes to 2D Horizontal Forces. Like with any forces problems, we'll practice the same sequence of steps:

Draw a loose frame diagram (FBD), ensuring to incorporate and label coordinate axesSet up Newton's Second Law equation ( ∑F = ma )Solve for the objective variable

The equations to convert between elements and magnitude-angle notation will all the time be useful once we're coping with forces at other angles

Calculating elements: 

Fx=|F⇀| cos θFy=|F⇀| sin θ

Looking on the nature of our downside, those equations shall be:

Fx=|F⇀|sin θFy=|F⇀|cos θ

This is as a result of for the x-direction, now we have reverse and hypotenuse and for y-direction, we've adjoining and hypotenuse to the angles.

Calculating magnitude: 

|F⇀|=Fx2+Fy2

Step 1: Draw a free body diagram (FBD)

We'll simplify our problem by way of presenting it in an FBD.

We'll use a same old coordinate machine the place forces to the appropriate will probably be regarded as to be in certain x-direction and forces upwards shall be in the certain y-direction. 

Remember, FAx is in opposition to the left, therefore damaging (- FAx)

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